Ex 6
Question
Solution
\(2018\pi-1009\times2\pi=\color{red}0\) correspond donc au point \(\color{red}I\).
\(\frac{403\pi}{2}-101\times2\pi=\color{red}-\frac{\pi}{2}\) correspond donc au point \(\color{red}J'\).
\(-\frac{47\pi}{3}+8\times2\pi=\color{red}\frac{\pi}{3}\) correspond donc au point \(\color{red}C\).
\(\frac{109\pi}{4}-14\times2\pi=\color{red}-\frac{3\pi}{4}\) correspond donc au point \(\color{red}H\)